Three infinitely long charge sheets are placed as shown in the figure. The electric field at point P is going to be
2σε0^k
−2σε0^k
4σε0^k
−4σε0^k
A
2σε0^k
B
−2σε0^k
C
4σε0^k
D
−4σε0^k
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Solution
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Step 1: Electric field due to a large charged sheet[Ref. Fig.]
Electric field due to the charged sheet with surface charge density σ is E=σ2ε0
Due to positve charge density field is away from sheet and due to negative charge density field is towards the sheet.
Step 2: Resultant field at point P
Electric field being a vector quantity, it will be added vectorially at a point.
→Ep=→E1+→E2+→E3
=σ2ε0(−^k)+−2σ2ε0(^k)+−σ2ε0(^k)
=−2σε0^k
Option (B) correct answer.
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