Assuming that all matrices are n x n and invertible, solve for D. BCAT DCBTA = BCT. OD = C-¹A BA-¹ (B7)¯'A-¹ OD = (B7) ¹A-CA-¹ (B7) C-¹ OD = (CT) CBTA (CT)-¹B-¹ OD= ATC-¹B-A-BTC-1 OD= (AT) C-CT A-¹ (B¹) C-1
Assuming that all matrices are n x n and invertible, solve for D. BCAT DCBTA = BCT. OD = C-¹A BA-¹ (B7)¯'A-¹ OD = (B7) ¹A-CA-¹ (B7) C-¹ OD = (CT) CBTA (CT)-¹B-¹ OD= ATC-¹B-A-BTC-1 OD= (AT) C-CT A-¹ (B¹) C-1
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter3: Matrices
Section3.5: Subspaces, Basis, Dimension, And Rank
Problem 63EQ
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