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 If N= (P₁) ˣ ×(P₂)ʷ ×(P₃) ʸ  Then no. of factors of N=(x+1) ×(w+1) ×(y+1)  For example: N = 50² × 14  Find the total factors, prime factors, composite.

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Presentation on theme: " If N= (P₁) ˣ ×(P₂)ʷ ×(P₃) ʸ  Then no. of factors of N=(x+1) ×(w+1) ×(y+1)  For example: N = 50² × 14  Find the total factors, prime factors, composite."— Presentation transcript:

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2  If N= (P₁) ˣ ×(P₂)ʷ ×(P₃) ʸ  Then no. of factors of N=(x+1) ×(w+1) ×(y+1)  For example: N = 50² × 14  Find the total factors, prime factors, composite factors, even factors and odd factors of N.

3  N = (5²×2)² ×7×2 =5⁴×2³×7 total no. of factors of N= 5 × 4×2 =40 Prime factors = 3 Composite factors = 40-3-1=36 Odd factors = 5 × 2 = 10 Even factors = 40-10= 30

4  Q.) N =100 ²×15  Find total no. of factors  Find total no. of factors which are multiple of 100  Q.) Find the total number of factors of 576?  Q.) If N = 12³×3 ⁴×5², find the total no. of even factors  Q.) How many factors of 1 crore would end with zero


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