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Question

A water jet, whose cross sectional are is a strikes a wall making an angle θ with the normal and rebounds elastically. The velocity of water of density d is V.
Force exerted on wall is


A
2 aV2dcosθ
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B
2 aV2dsinθ
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C
2 aVdcosθ
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D
aVd cosθ
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Solution

The correct option is A 2 aV2dcosθ
Change in momentum
Δp=mVcosθ(mVcosθ)=2 mV cosθ
Force acting on the wall
F=dpdt=(2 Vcosθ)dmdt

The mass crossing an area in time t for a small element would be
m=V×t×a×d.....(1)

dmdt=VadF=2aV2dcosθ

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